View Full Version : Q.44.
Manish Salian
6th October 2006, 10:13 AM
Hi,
After giving the long explanation to Q.46, here are the standings:
Anil: 26 points (-5 for Q.64 & Q.62 and -2 for Q.59)
Robin: 23 points
Rishabh: 19 points (-2 for Q.64)
Minnat: 18 points (-2 for Q.62, -2 for Q.61)
Piyush: 12 (-2 for Q.62)
Abhinav: 11 points
Ruchira: 3 points (-2 for Q.54)
Lajja: 2 points
Ankita: 2 points (-5 for Q.54)
Mohammed: 0 points (-2 for Q.52)
Nisha: 0 points (-5 for Q.63)
And here the question for today:
Q.44.
In a game called flip it or dip it, three people flip coins, and the odd person out has to pay the others double what they have already won. After three games, each person has lost twice and has Three hundred and sixty Rupees. How much did each start with?
Regards,
Manish sir
AnilkumarBDaga
6th October 2006, 11:17 AM
Hello Sir,
The question is:
Q.44.
In a game called flip it or dip it, three people flip coins, and the odd person out has to pay the others double what they have already won. After three games, each person has lost twice and has Three hundred and sixty Rupees. How much did each start with?
From the question I have understood that "and the odd person out has to pay the others double what they have already won." this means if anyone wins in the first round then their amount would be increased by double of what they already have.
I have also assumed that these are the first three games played by them - which seems to be a very safe assumption.
Under the light of above understanding or assumption - my answer is:
That they start with Rs. 733.33, 253.33 and 93.33 respectively.
These are the amounts of people losing the first, second and the third games respectively.
This question can be solved by bottom-up approach. i.e. the amount at the end of the third round are equal at 6:6:6.
For getting the values as at the end of second round we simply need to back-calculate.
eg. If we assume that 3rd person lost the game in the 3rd round then the ratios of money with 1st, 2nd and the 3rd person would simply become 2:2:14. So on and so forth we can calculate the values as at the start of the game (first round) which turns out to be 55:19:7.
P.S. Modifications to my answer below.
Thanks & Regards,
Anil Daga
RishabhShah
6th October 2006, 11:25 AM
helo...
nice to c everyone... im here my vacs are over....
welll anil tell me one thing when in a game only one can lose.. how is it possible tht in three games everyone has lost twice...
AnilkumarBDaga
6th October 2006, 11:34 AM
Hi Rishabh,
Look at it from other side. In each game only one is winning. Hence (n-1) are losing; where n being the number of participants in each of the rounds.
Hence in this case 3 being the number of participants; 2 people are losing every round.
Thanks,
Anil Daga
RishabhShah
6th October 2006, 12:18 PM
no the statement clearly states that the one who loses has to pay double to OTHERS.. this other signifies that there are two winners in the game... so how is it possible that there are two losers in every game
AnilkumarBDaga
6th October 2006, 10:41 PM
Hi Rishabh,
You have an interesting point.
But I would modify my answer accordingly:
If anyone is the odd one out he is the winner as per the rules of the game and pays the losers. (the question does not say anything about being odd one out and hence - i wud say that odd one out is the winner). So we have 2 losers in each round - and satisfies all the other conditions of the game.
Thanks,
Anil Daga
Manish Salian
8th October 2006, 11:18 PM
Thanks Rishabh for pointing the flaw in the question!! I will give you two points for the same!!
Anil you don't lose anything, but don't win anything either. But you may answer the corrected question as given below:
Q.44.
In a game called flip it or dip it, three people flip coins, and the odd person out has to pay the others double what they have already won. After three games, each person has lost once and has Three hundred and sixty Rupees. How much did each start with?
Yes, Anil and Rishabh! Now you may post your answers...
I will keep the deadline for this question till Monday midnight only!!
Regards,
Manish sir
AnilkumarBDaga
9th October 2006, 09:15 AM
Hello Sir,
In the light of the new situation my answer would still be the same.
That they start with Rs. 733.33, 253.33 and 93.33 respectively.
These are the amounts of people losing the first, second and the third games respectively.
This question can be solved by bottom-up approach. i.e. the amount at the end of the third round are equal at 6:6:6.
For getting the values as at the end of second round we simply need to back-calculate.
eg. If we assume that 3rd person lost the game in the 3rd round then the ratios of money with 1st, 2nd and the 3rd person would simply become 2:2:14. So on and so forth we can calculate the values as at the start of the game (first round) which turns out to be 55:19:7.
Thanks & Regards,
Anil Daga
PiyushTantia
9th October 2006, 05:58 PM
Hello sir,
i think Anil is correct.
he has given a good explanation for the same. so, i'm wid him..
RishabhShah
9th October 2006, 11:36 PM
helllooo.......... sorry to be late but i m back...
well thank u sir for appreciating that...
welll now its perfect anil... he is rite theans is 733.33, 253.33, 93.33( though 1 paisa still misin lol ) bye tc godbless....
Manish Salian
11th October 2006, 07:29 AM
Hi,
I am afraid, all three of you are wrong!! After all that spat, all of you have lost points!!
As Anil pointed out, we can work this out by "Bottoms-Up" approach. In other words, start by each person having Rs.360 and make them lose once sequentially in every round!
The amount with them after Round 3 is as follows:
Person 1 : Rs.360
Person 2 : Rs.360
Person 3 : Rs.360
Let us say that Person 3 loses the third round. So, he must have given Rs.180 to Persons 1 and 2 (that is how they would have doubled their sums). So the amounts with them after Round 2 would have been:
Person 1 : Rs.180
Person 2 : Rs.180
Person 3 : Rs.720
Now, if Person 2 loses in the second round, he would have given Rs.90 to person 1 and Rs.360 to person 3. So the amount with them after Round 1 would be:
Person 1 : Rs.90
Person 2 : Rs.630
Person 3 : Rs.360
Finally, let person 1 lose the first round. This would mean he would have shelved out Rs.315 to person 2 and Rs.180 to person 3. So the amounts that they would have started with are as given below:
Person 1 : Rs.585
Person 2 : Rs.315
Person 3 : Rs.180
Now, these are the amounts that they started with and not the one mentioned by Anil and seconded by Rishabh and Piyush.
Anil, you lose 5 marks, and Piyush and Rishabh you lose 2 marks each.
Regards,
Manish sir
vBulletin v3.5.1, Copyright ©2000-2010, Jelsoft Enterprises Ltd.